When (a ne 0), there are two solutions to (ax^2 + bx + c = 0) and they are
[latex]x = {-b pm sqrt{b^2-4ac} over 2a}[/latex]
$$x = {-b pm sqrt{b^2-4ac} over 2a}.$$
(x = frac{-bpmsqrt{b^2-4ac}}{2a})
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Where grounded conductors of different systems are installed in the same raceway, cable, box, auxiliary gutter, or other type of enclosure, each grounded conductor shall be identified by _______.
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